Re: [計量] 請教來欣數學M3~

看板GRE (GRE入學考試)作者 (bibo)時間18年前 (2007/09/30 22:28), 編輯推噓1(100)
留言1則, 1人參與, 最新討論串2/2 (看更多)
※ 引述《whisperheart (mione￾  ￾ ￾N￾ ￾ )》之銘言: : 1. A tourist purchased a total of $1500 worth of traveler's check in $10 : and $50 denominations. During the trip the tourist casehed 7 checks and then : lost all of the rest. If the number of $10 checks cashed was one more or : one less that the number of $50 checks cashed, what is the minimum possible : value of the checks that were lost? : (A) $1430 : (B) $1310 : (C) $1290 : (D) $1270 : (E) $1150 答案是D 假設消耗的七張check中,有x張是十元的,y張是五十元的 根據題目的意思x+y=7 且 x=y+1 或 x=y-1 ->兩種可能 但是題目最後問minimum possible value of the checks that were lost 也就是你先前花越多錢,損失越少,故選 x=y-1 (這樣五十元check比十元的多花一張) 故 x+y=y-1+y=2y-1=7 2y=8 y=4 所以 x=3 消耗金額= 3*10+4*50=230 所求=丟掉的金額=1500-230=1270 : 7. Tickets for all but 100seats in a 10000-seat stadium were sold. Of the : tickets sold, 20 percent were sold at half price and the remaining tickets : were sold at the full price of $2. What was the total revenue from : tickets sales? : (A) $15840 : (B) $17820 : (C) $18000 : (D) $19800 : (E) $21780 答案是B 由題目知道賣出9900個位子 其中 20 percent were sold at half price 故另外80 percent (remaining tickets)were sold at the full price($2) 得知票的半價為一塊 故 9900*20%*1=1980 9900*80%*2=15840 1980+15840=17820 大概是這樣吧XD -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.243.79

09/30 23:14, , 1F
恍然大悟!!感謝~~
09/30 23:14, 1F
文章代碼(AID): #16_xAOuP (GRE)
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文章代碼(AID): #16_xAOuP (GRE)