Re: [計量] 可以幫幫我解幾題數學嗎??

看板GRE (GRE入學考試)作者 (追求卓越近乎苛求)時間18年前 (2007/10/25 00:16), 編輯推噓0(001)
留言1則, 1人參與, 最新討論串3/3 (看更多)
※ 引述《bluesink (美女又怎樣)》之銘言: : 1. coins are be put into 7 pockets so that each pocket contains ar least one : coin. At most 3 of the pockets are to contain the same number of coins and : no two of the remaining pockets are to contain an equal number of coins. : What is the least possible number of coins needed for the pockets? : (A) 7 : (B) 13 : (C) 17.......answer : (D) 22 : (E) 28 可以解釋成最後會有五種相異錢幣數目 其中一種數目*3 那五種相異數目最小的組合就是12345 如果要讓其中一個數字*3然後還是最小 那個*3的就只能選1 得 sum(1112345)=17 : 2. During a certain season, a team won 80 percent of its first 100 games and 50 : percent of its remaining games. If the team won 70 percent of its games for : the entire season, what was the total number of games that the team played? : (A) 180 : (B) 170 : (C) 156 : (D) 150......answer : (E) 105 Won percentage(勝率)= won#/total game# Assume totally they played x games during the first 100 games, it won 80 ==> 80/100, while in the rest x-100 games, they won 50% ==> they won (x-100)/2 games Therefore, # of total games they won is 80+(x-100)/2 winning percentage = 70% = [80+(x-100)/2] / x, solve x, and x=150 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 203.70.188.243

10/25 00:25, , 1F
感謝你幫我解答喔!
10/25 00:25, 1F
文章代碼(AID): #177s_p1x (GRE)
文章代碼(AID): #177s_p1x (GRE)