Re: [計量] CAT計量問題請教

看板GRE (GRE入學考試)作者 (Paradise)時間16年前 (2009/08/05 21:56), 編輯推噓0(001)
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※ 引述《think12381 ()》之銘言: : 沒人可以問 只能請教各位板友 這些題目怎麼算 : 不好意思題目還蠻多的 : CAT 14 : 25. : Pat plans to visit the national gallery oncee each month in 2007 : except in july and august when he plans to go three times each a single : admission costs $3.5 a pass valid for unlimited visits in any : 3-month period can be purchased for $18 and annual pass costs $60 : what is the least amount in dollars that pat can spend for his intended number : of visits : ans 49.5 九次買單次票,然後暑假的時候買單季套票 例如說用季票看7,8,9或者6,7,8 cost = 3.5x9 + 18 = 35 + 18 - 3.5 = 49.5 : CAT 15 : 1. : The figure above shows part of a circle whose : circumference is 45 if arcs of length 2 and length b : continute to alternatee around the entire circle so that : there are 18 arcs of each length, what is the degree : measure of each of the arcs of length b : ans 4' 圖咧? : 6. : if the product consecutive integers is equal to one of them : what is the largest possible value of one of the integers : ans 5 我要再想想 : 14. : an interger is "conjoint" is a muliple of 2 or 3 : how many conjoint integers are there between -11 and 11 : ans 15 順便問題意 如果是2或者3的倍數,吾人稱之為conjoint 列舉出在-11到11之間符合條件者: -10, -9, -8, -6, -4, -3, -2, 0..... 請留意0也是其(任意兩者)倍數 : 18. : eason some goldfish at the state fair during the first : week 1/5 of them died and during the second week 3/8 of : those still alive at the end of the first week died what : fraction of the original goldfish were still alive after : two weeks : ans 1/2 這題目真是好樣的 他說在第一週時 1/5死了,在第二週時第一週活下來的3/8死了 所以活著的 = 1 - 1/5 - 4/5 * 3/8 = 1 - 1/5 - 3/10 = 1/2 : CAT16 : 13. : x and y are distinct positive decimals. if sum of x and y : were rounded to the hundredth the result would be equal to x : y 0.007 : ans B 題目有點抽像,不過可以猜想不管y是什麼,x加上他 但是再做四捨五入到百分位後依然是x 直接看選項,不管x是多少加上0.007之後一定會進位,所以B比較大 : 28. : the slope of line m that through O and intersects AB 3/8 : between A and B : ans B 不懂@@ : CAT 17 : 25. : of ten researchs attending a round-table meeting, two are husband and wife : what is the probability that the couple will sit adjacently : ans 2/9 先考慮夫妻倆為一個單位,故有9個單位 但是考慮夫妻兩人可換位,所以共有 9! x 2 / 9 種可能 而sample space為 10!/10 故機率為 8! x 2 / 9! = 2 / 9 : 27. : there are 27 students on the school debate team. : what is the probablity that at least 3 of them have : their birthdays in the same month : ans 1 這個很像很有名的 birthday paradox,個人認為考這個應該是h的問題了 他問至少三個,機率的概念就是想成少於兩個 (其實就是只有兩個) 所以就是 (1/12) x (11/12)^25 (*) 但是所求為 1 - (*) 這個機率非常小,所以看到 1 就可以選了 ^^|| -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 221.169.5.190

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文章代碼(AID): #1AUO-G6n (GRE)
文章代碼(AID): #1AUO-G6n (GRE)