[計量] 請教一題計量

看板GRE (GRE入學考試)作者 (scure)時間15年前 (2010/10/23 18:31), 編輯推噓1(107)
留言8則, 2人參與, 最新討論串37/41 (看更多)
for a light that has an intensity of 60 candles at its source, the intensity in candles, S, of the light at a point d feet from the source is given by the formula S=60k/(d^2) , where k is a constant. if the intensity of the light is 30 candles at a distance of 2 feet from the source, what is the intensity of the light at a distance of 20 feet from the source? Ans: 3/10 candles 拜託各位高手了,文意實在不好理解... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.36.61.42

10/23 18:39, , 1F
有個光源在他光源處強度為60 candles
10/23 18:39, 1F

10/23 18:39, , 2F
而且他強度會隨遠離光源變化,當距光源d時強度可以表
10/23 18:39, 2F

10/23 18:40, , 3F
示為S=60k/(d^2),單位為candles,k為常數。
10/23 18:40, 3F

10/23 18:41, , 4F
如果今天距離光源2feet處光源強度30candles
10/23 18:41, 4F

10/23 18:42, , 5F
列式: 30=60*k/(2^2) 所以k=2。
10/23 18:42, 5F

10/23 18:42, , 6F
題目要問離光源20feet遠時強度多少candles。
10/23 18:42, 6F

10/23 18:43, , 7F
S(at20feet)=60*2/(20^2)=3/10candles
10/23 18:43, 7F

10/23 19:46, , 8F
感謝i大,果然是文意...
10/23 19:46, 8F
文章代碼(AID): #1CmhcVyw (GRE)
文章代碼(AID): #1CmhcVyw (GRE)