Re: [計量] GWD6-25,28

看板GMAT (GMAT入學考試)作者 (zingy)時間17年前 (2007/12/26 20:23), 編輯推噓0(000)
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※ 引述《NOWIZKI (== ==)》之銘言: : Q25: : If the number 52,1n9, where n represents the tens digit, is a multiple of 3, : then the value of n could be which of the following? : A. 6 : B. 5 : C. 3 : D. 1 : E. 0 : Answer: d 我猜是因為那個","讓您迷惑了!! 有一個數 521n9 可以被3整除 則n可能是 5+2+1+n+9=17+n 可以被3整除 故n=1,4,7 所以是D : Q28: : Last Sunday a certain store sold copies of Newspaper A for $1.00 each and : copies of Newspaper B for $1.25 each, and the store sold no other newspapers : that day. If r percent of the store’s revenues from newspaper sales was from : Newspaper A and if p percent of the newspapers that the store sold were : copies of newspaper A, which of the following expresses r in terms of p? : A. 100p / (125 – p) : B. 150p / (250 – p) : C. 300p / (375 – p) : D. 400p / (500 – p) : E. 500p / (625 – p) : Answer: d : 請問一下這兩題要怎麼去解 去大陸的網站看就只有一個不懂而已 設共賣出 X 份 A 的收益= X*p%*1 B 的收益= X*(1-p%)*1.25 X*p% A報的收益 _______________________ _______________ r= X*(1-p%)*1.25 + X*p%*1 = A報+B報 的收益 =400p/(500-p) ^^ 我湊不到這100怎麼來的...T_T -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.217.218.247 ※ 編輯: zingy 來自: 61.217.218.247 (12/26 20:41)
文章代碼(AID): #17SaVGt5 (GMAT)
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