[問題] 奇數偶數問題 from 高分突破 P240

看板GMAT (GMAT入學考試)作者 (^O^)時間16年前 (2009/12/12 15:44), 編輯推噓1(106)
留言7則, 2人參與, 最新討論串1/1
問題: Jerome wrote each of the integers 1 through 20, inclusive, on a separate index card. He placed the cards in a box, then drew cards one at a time randomly from the box,without returning the cards he had already drawn to the box. In order to ensure that the sum of all the cards he drew was even, how many cards did Jerome have to draw? (1) 19 (2)12 (3)11 (4)10 (5)3 答案是12 但是12張有可能是五張奇數 七張偶數 加起來還是奇數 這題正解應該是多少? 謝謝^^ -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.170.32.28

12/13 00:17, , 1F
這題是問要抽多少張,保證和會是偶數,因此要看最極端
12/13 00:17, 1F

12/13 00:18, , 2F
的情況,也就是,最先抽出了一張奇數牌,然後連續抽了
12/13 00:18, 2F

12/13 00:19, , 3F
十張偶數的牌,這時,抽到第十二張,得到另一個奇數時
12/13 00:19, 3F

12/13 00:19, , 4F
全部的和才成為偶數。而你所提的情況,一定在當中某張
12/13 00:19, 4F

12/13 00:20, , 5F
牌時,就會讓整體的和成為偶數,因此所需要的張數會小
12/13 00:20, 5F

12/13 00:20, , 6F
於十二張。所以最多是十二張。
12/13 00:20, 6F

12/13 10:26, , 7F
感謝 我了解了~
12/13 10:26, 7F
文章代碼(AID): #1B8qdSWD (GMAT)
文章代碼(AID): #1B8qdSWD (GMAT)