Re: [計量] 印度網站的Q 數題

看板GRE (GRE入學考試)作者 (=口=)時間17年前 (2009/05/26 22:48), 編輯推噓1(100)
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※ 引述《KRZYSZ (VICTORIA)》之銘言: : Given a series. : 1, 1/(2t), 1/(2)^2*t, 1/(2)^2*(t)^2 ................. : For t=2, if odd terms are 1/2 times the previous number and even terms are : 1/(t) times the previous number, then : Col A: The eight term (8th) in the series : Col B: 1/(2)^8 : Ans: C 因為t=2 序列為 1,1/4,1/8,1/16....1/2^n 所以第八個是1/2^8 : it really seems strange to me as the question describes that t=2 : and gives the series at the begining. : the question seems to have two different definitions of the series? : In a contest, there are 5 judges who are to rate (they can rate from 0-10) : the scores of 8 different groups. : Category Scores : Solo 14 : Group 17 : xxxx 25 : xxxx 29 : xxxx 31 : xxxx 35 : xxxx 44 : xxxx 49 : What is the minimum number of teams, which must get 7 or more than 7 score : from atleast one judge? : Ans:4 至少從一位裁判得到至少七分以上 = 全部 - 沒有從任任裁判得到至少七分以上 = 全部 - 所有裁判都給六分以下 = 全部 - 總分小於30分的隊伍 = 8-4 = 4 : how and what concept should i have to cope with the question like this? : Given stock price at end of February as x. If stock price increase in March : is 10% & increase in April is again 10% and if May price = 70% of April : price, then : Col A: The May price : Col B: 0.9x : Ans: B : isn't the price in March x*110% ? : or is that i misunderstand the meaning of the question : Thank you guys for answering my questions ._. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.113.201.204

05/27 10:50, , 1F
3Q3Q3Q~~!!!
05/27 10:50, 1F
文章代碼(AID): #1A7054vI (GRE)
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文章代碼(AID): #1A7054vI (GRE)