Re: [計量] 請教幾題數學

看板GRE (GRE入學考試)作者 (阿KEI)時間15年前 (2010/11/23 17:40), 編輯推噓1(101)
留言2則, 2人參與, 最新討論串6/6 (看更多)
※ 引述《sonatach (sonata)》之銘言: 1. Par drove to work from his home, averaging 40 miles per hour, and was 12 minutes late. The next day he left home for work at the same time, took the same route, averaging 48 miles per hour, and was 7 minutes late. How far in miles is it from Pat's home to his work? Ans: 20.0 第一天 距離=D 時間=T 速率 40=D/T 第二天 距離不變 時間=T-1/12 速率 48=D/(T-1/12) 1/12是因為 第二天快了5分鐘 也就是1/12小時 2. If an employee deposited $2000 in a new credit union account and made a single $200 deposit during each month thereafter, after how many deposits will the employee have deposited a total of $ 10,000 in the credit union account? Ans: 41 1+[(10000-2000)/200] =41 如果要列式的話應該是這樣吧 3. If the smaller of 2 consecutive odd integers is a multiple of 5, which of the following could NOT be the sum of these 2 integers? (A) -8 (B)12 (C)22 (D)52 (E) 252 Ans: (c) 其實不要設比較好 因為設方程式之後 要一個一個答案帶進去算 這樣要花很久 不過如果要用你的方法設的話 第二個奇數要設5(2x+1)+2 4. If rt > st and r > s, then which of the following must be true? (A) t > 0 (B) s > 0 (C) r > 0 (D) t < 0 (E) rs > 0 Ans: (A) 滿直觀的 5. If x < x的3次方 < x的平方, then which of the following could be the possible value of x? (A) -3/2 (B) -1/2 (C) 0 (D) 1/2 (E) 1/3 Ans: (B) 只要是負的小數都可以 6. A candidate for public office allocated 1/3 of her campaign funds for television appearances, 2/3 of the remainder for personal appearances, and the balance for newspaper advertisements. If the amount allocated for newspaper advertisements was equally divided among 4 newspapers, what fraction of her original campaign funds was allocated for each newspaper? Ans: (A) 1/18 推文有人解釋了 7. 0.0625y = x(2.5/4) Col A: x Col B: y Ans: D 移項一下 0 < 0.0625 * (2.5/4) =x/y x,y皆為正跟皆為負 大小相反 所以無法比較 8. If d>0 and 0 < 1- (c/d) < 1, which of the following must be true? I. c > 0 II. c/d < 1 III. c^2 + d^2 >1 Ans: I. and II. 題幹可以知道 0 < c/d < 1 只知道比值無法知道真正的值 舉個例 c/d = 0.5 c=1 d=2 c^2+d^2 >1 但 c=0.1 d=0.2 c^2+d^2 <1 所以 III 不成立 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.166.9.74 ※ 編輯: sonatach 來自: 218.166.9.74 (11/23 12:33)

11/23 12:29,
2.(10000-2000)/200=40, 40+1(第一次)=41
11/23 12:29

11/23 12:36,
5.我不懂你意思...-1/2不對嗎?!....
11/23 12:36

11/23 12:38,
7.正負號可以直接逆轉比大小,你交換各代1,-1試試看
11/23 12:38

11/23 12:43,
不好意思第5題我耍笨了..一直以為-1/2 比-1/8大 = =
11/23 12:43

11/23 12:45,
8.兩個都分數的情況下,III就不對了.
11/23 12:45

11/23 12:47,
6.2/3 of the remainder意思是剩餘的2/3的2/3,然後
11/23 12:47

11/23 12:48,
2/3的1/3"餘額"就是給newspaper
11/23 12:48

11/23 12:50,
所以4/18/4=1/18
11/23 12:50

11/23 12:51,
啊...用推文功能回文真難用 o_O
11/23 12:51

11/23 13:02,
3. 要設5(2n+1)和5(2n+1)+2 即可解出
11/23 13:02

11/23 13:26,
4. B代入答案是對的 你再試一次^^
11/23 13:26

11/23 13:27,
說錯 是第5題
11/23 13:27

11/23 13:31,
1. 先把單位Hour改成minute 然後用距離除以速度,就
11/23 13:31

11/23 13:31,
會得到各別的時間 兩個相減就可得時間差 而時間差
11/23 13:31

11/23 13:37,
就是題目給的遲到時間的差
11/23 13:37
-- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.195.56.20 ※ 編輯: Ykei 來自: 123.195.56.20 (11/23 17:42)

11/23 17:45, , 1F
案成R了 不知道怎麼改成回文 就這樣吧QQ
11/23 17:45, 1F

11/24 00:21, , 2F
謝謝三位大大 終於搞懂了...
11/24 00:21, 2F
文章代碼(AID): #1Cwulq_b (GRE)
文章代碼(AID): #1Cwulq_b (GRE)