[請益] 一題國三理化力學題
學生問了一題看似簡單的題目
一個70kg的人
已知他若能跳高離地0.7m就能灌籃
那此人必須向地板出多少kgw的力
才能達到 而那又是幾焦耳?
(不考慮其他因素)
我想前一個應該是用F=ma S=1/2gt^2 還有W=FS
後一個是用位能公式
但算起來好像怪怪的 往上跳的出力所得的a應該也稍微抵銷g的-a吧?
可以請大家幫忙算一下嗎
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