Re: [計量] GWD19-22 19-34

看板GMAT (GMAT入學考試)作者時間16年前 (2008/09/06 21:00), 編輯推噓1(100)
留言1則, 1人參與, 最新討論串2/2 (看更多)
※ 引述《qqopqqop (p )》之銘言: : 22 : A researcher plans to identify each participant in certain medical experiment : with a code consisting of either a single letter or a pair of distinct letters : written in alphabetical order. What is the least number of letters that can : be used if there are 12 participants, and each participant is to receive a : different code? : Ans 5 : 我自己算8>< : 34 : Of the 2500 tons of ore mined daily at a quarry, o.4 percent results in a : certain pure metal. In how many days of mining will the total amount of : pure metal produced at the quarry be equal to the daily amount mined? : Ans 1000 : 28 : A school administratior will assign each student in a group of n students : to one of m classroom. If 3<m<13<n, is it possile to assign each of the : n students to one of m classrooms so that each classroom has the same number of : students assigned to it. : 1 It is possible to assign each of 3n students to one of m classrooms so that : each classroom has the same number of studnent assigned to it : 2 It is possible to assign each of 13n students to one of m classrooms so that : each classroom has the same number of students assigned to it : Ans b : 希望有人可以幫我一下 : 希望有好心人士可以幫我解惑 大感激 先解Q22 用1個字母可有 1 種編法 2 2 + C2取2 = 3 種 3 3 + C3取2 = 6 種 4 4 + C4取2 = 10種 5 5 + C5取2 = 15種 ..........至少要5個字母# Q34 答案應該是C吧!? 每天可得 2500*0.4% = 10 tons pure metal 10x = 2500,x = 250# Q28 題目看似複雜其實只是問你m能不能整除n而已 (1) m可以整除3n--> m = 4、n = 16則m整除n m = 6、n = 14則m不能整除n ...... insufficient (2) m可以整除13n-->因為m小於13,若m可以整除13n,則m一定是n的因數 故m可以整除n ......sufficient Ans: B ※ 編輯: catspace 來自: 118.168.235.249 (09/06 21:14)

09/07 12:24, , 1F
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09/07 12:24, 1F
文章代碼(AID): #18mdy1GG (GMAT)
文章代碼(AID): #18mdy1GG (GMAT)