[計量] pp2-ps76
A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist
traveling in the same direction along the same path at a constant rate of 20
miles per hour. The cyclist stops to wait for the hiker 5 minutes after
passing her, while the hiker continues to walk at her constant rate. How
many minutes must the cyclist wait until the hiker catches up?
the answer is 20
有點不太懂題目
請問有人會嗎?
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 124.6.11.107
討論串 (同標題文章)
以下文章回應了本文：
完整討論串 (本文為第 1 之 4 篇)：
GMAT 近期熱門文章
PTT職涯區 即時熱門文章
