[問題]請問一題計量的敘述

看板GRE (GRE入學考試)作者 (A&F愛好者)時間15年前 (2011/04/20 13:00), 編輯推噓2(205)
留言7則, 4人參與, 最新討論串1/1
CoA : A number whose square is 4 less than twice the square of 10 CoB : 15 答案是B 我翻譯成 X^2 = 4 < 2*10^2.....感覺好怪,搞不太清楚要算什麼 麻煩好心的大大解答 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.166.199.153

04/20 13:06, , 1F
x平方比10平方的兩倍少4
04/20 13:06, 1F

04/20 13:07, , 2F
也就是X^2 + 4 = 10^2 x 2
04/20 13:07, 2F

04/20 13:08, , 3F
*
04/20 13:08, 3F

04/20 13:08, , 4F
我猜是 x^2 = 2*10^2-4 = 196, than x = 14, B>A無誤
04/20 13:08, 4F

04/20 13:09, , 5F
算出來X是14所以B大
04/20 13:09, 5F

04/20 13:09, , 6F
x^2 = 2*10^2 -4 -> x=14 or -14 < 15
04/20 13:09, 6F

04/20 14:29, , 7F
喔喔喔,原來我誤解4 less感謝各位
04/20 14:29, 7F
文章代碼(AID): #1DhcXzrE (GRE)
文章代碼(AID): #1DhcXzrE (GRE)