Re: [問題] GWD-6-19 Math

看板GMAT (GMAT入學考試)作者 (海鮮不新鮮)時間13年前 (2012/08/19 13:12), 編輯推噓1(100)
留言1則, 1人參與, 最新討論串2/2 (看更多)
※ 引述《dogdog915 (Lyndi)》之銘言: : If 2 different representatives are to be selected at random from a group of : 10 employees and if p is the probability that both representatives selected : will be women, is p > 1/2? : (1) More than 1/2 of the 10 employees are women. : (2) The probability that both representatives selected will be men is less : than 1/10. : 答案是E : (1) 我知道女性至少6個, 所以P= C(6,2) / C(10,2) = 1/3 -->insufficient : 請問(2)該如何解呢? : 謝謝! Let w be the number of female employees, then (10-w) is the number of male employees. Note that w is a non-negative whole number and is no more than 10. According to the description of the question, we have to know whether w 10-w C x C 2 0 w(w-1) 1 p = -------------- = ---------- > --- 10 10 x 9 2 C 2 <=> w(w-1) > 45 ? <=> w is more than or equal to 8 ? <=> w = 8 or 9 or 10 ? (1) alone gives us w > 5 => not sufficient! {for example, p < 1/2 if w = 6 and p > 1/2 if w = 8} 10-w w C x C 2 0 (10-w)(10-w-1) (10-w)(9-w) 1 (2) alone implis that --------------- = ---------------- = ------------- < ---- 10 10 x 9 90 10 C 2 => (10-w)(9-w) < 9 => w = 7 or 8 or 9 or 10 => not sufficient! {for example, p < 1/2 if w = 7 and p > 1/2 if w = 8} (1) & (2) together give us w = 7 or 8 or 9 or 10 => not sufficient! {for example, p < 1/2 if w = 7 and p > 1/2 if w = 8} Thus you have to choose (E). -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.136.110.45

08/20 13:53, , 1F
got it! thanks:)
08/20 13:53, 1F
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