Re: [計算] 指數律小哉問

看板tutor (家教)作者 (不可測之五度空間)時間16年前 (2009/08/04 13:20), 編輯推噓0(000)
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: 推 iambahamut:以2^3^2為例 依照上面算法會是2^9=512 08/03 21:39 http://lmgtfy.com/?q=2%5E3%5E2 (誤) : → iambahamut:實際是2^3=8 8^2 =64 = 2^6 08/03 21:40 : → iambahamut:指數算法其實直接相乘就好原式=(5^4)^(2x3)=5^4^6 08/03 21:41 : → iambahamut:5^4^6=5^24 答案就是5的24次方 08/03 21:41 : 推 iambahamut:除非原意是5^[4^(3^2)]才會是上面這個答案 08/03 21:44 一般情況而言 ,只有(a^m)^n =a^mn ,而沒有 a^m^n=a^mn a^m^n讀法是 "a的 m^n次方" (要計算結果則先計算 m^n) 而不是 "a^m的n次方" (要計算結果則先算 a^m ) http://en.wikipedia.org/wiki/Exponentiation 看這段 : [edit] Identities and properties . . . Similarly, while addition and multiplication are associative (for example, (2+3)+4 = 9 = 2+(3+4) and (2·3)·4 = 24 = 2·(3·4), exponentiation is not associative either: 23 to the 4th power is 84 or 4096, but 2 to the 34 power is 281 or 2,417,851,639,229,258,349,412,352. Without parentheses to modify the order of calculation, the order is usually understood to be top-down, not bottom-up: 以上淺見 ,有錯請指正 ^^/ ps....如果要說wiki的資料不見得正確的話 ,煩請各位幫忙找更有說服力的教材><;; -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 220.134.58.144
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