Re: [計量] PP2-PS 3.4.18.33.43題

看板GMAT (GMAT入學考試)作者 (yeeN￾N  N￾ )時間16年前 (2008/06/16 21:29), 編輯推噓1(100)
留言1則, 1人參與, 最新討論串2/2 (看更多)
※ 引述《amateurptt (剩自己了...)》之銘言: : ========================================================================= : 3. A certain taxi company charges $3.10 for the first [?] of a mile : plus $0.40 for each additional of a mile. What would this company : charge for a taxi ride that was 8 mile long? : (A)$15.60 : (B)$16.00 : (C)$17.50 : (D)$18.70 : (E)$19.10 : ans:D : 我的解法如下,請各位幫我看哪有出問題 : 3.10 + 7*0.40 但是與答案差相當多,我看錯題目嗎? 這題應該是題目不完全,PP裡面有出現[?]的就表示有缺的圖檔 : ============================================================================ : 4.In a stack of boards at a lumber yard, the 20th board counting from : the top of the stack is immediately below the 16th board counting from : the bottom of the stack. How many boards are in the stack? : (A)38 : (B)36 : (C)35 : (D)34 : (E)32 : ans:D 想請問解題思路 這題首先要看的懂題目在問什麼,題目是說有一堆板子的堆疊,從最上面數下來的第20 塊板子在從最下面數上來的第16塊板子的下面;這題可以簡化題型,你可以拿5個硬幣 疊一疊,從上面數下來第4個硬幣在從下面數上來的第三個硬幣的下面,問總共有幾個? : =========================================================================== : 18. 3 teaspoons = 1 tablespoons : 4 tablespoons = [?] cup : According to the information above, how many teaspoons are equal to [?] cup? : (A)3 : (B)4 : (C)9 : (D)12 : (E)18 : ans: E 一樣想請問解題思路 同第三題的說明 : =========================================================================== : 33.If x^4 + y^4 = 100, then the greast possible value of x is between : (A) 0 and 3 : (B) 3 and 6 : (C) 6 and 9 : (D) 9 and 12 : (E) 12 and 15 : ans:B : 我原以為題目要x最大,所以就要y^4為0 : 也就是 直接求x^4=100 ,x的最小值為? : 但是答案不對,想請求正解! 你原本的想法沒錯,題目是要求x最大可能的值的範圍為何? x要為最大,所以y^4=0 x=3時,x^4=81 ------(1) x=4時,x^4=256 ------(2) 由(1)(2)可知x介於3到4之間,答案符合的就是(B) : ============================================================================ : 43.A committee of three people is to be chosen from four married couples. : What is the number of different committees that can be chosen if two people : who are married to each other cannot both serve on the committee? : (A)16 : (B)24 : (C)26 : (D)30 : (E)32 : ans:E : 我的解法是 : 4 2 : C * C = 8 四對couples中選出三對 * 兩個人選一 : 3 1 : 似乎思路出了問題, 希望高手指正! 四對couples中選出三對*選出的三對中的每對選一人 也就是 4 2 2 2 C * * * = 32 3 1 1 1 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.193.123.220

06/16 22:54, , 1F
謝謝大家熱心解惑~~~我都很清楚了解了~~感謝大家~~
06/16 22:54, 1F
文章代碼(AID): #18LcgeMo (GMAT)
文章代碼(AID): #18LcgeMo (GMAT)