[請益] n個醉漢的漫步？
假設現在有一個醉漢，他以隨機漫步（Random Walk）從酒館走到家中的平均時間為T。
那麼現在有n個醉漢，都用隨機漫步移動，第1個醉漢回到家中
（嗯...假設他們都住同一個地方...）平均所需花費的時間為何？
這樣說好像很無厘頭...
恩...換個形式來講。
空間中有A,B兩點。
從A點釋放一團花粉，作布朗運動晃到B點的所需平均時間為T。
則從A點釋放n團花粉，至少有一團作布朗運動晃到B點的平均時間為何？
我想這兩個說法本質上應該是相同的...如果我是錯的，當然也請告訴我。
這並不是個作業想找人來回答...我只是今天在洗澡時突發奇想而已。
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