[解題] 高一數學
1.年級:高一
2.科目:數學
3.章節:一
4.題目:
求與3x+4y=5 平行的直線
其截距合為10 的直線
5.想法:
設直線交x軸於(a,0) y軸(0,10-a)
兩點的斜率會等於-3/4
10-a 3
____ ____
= -
-a 4
則a=40/7 y= -3/4(x-40/7)
21x+28y=120
答案是3x+4y+24=0
3x+4y-24=0 請問那裡算錯了嗎XD 謝謝
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